Section Solutions
¶Critical Points
\((0,0,1)\) is a max
none, why?
\((0,1, 4)\) is a min
\((0,0,0)\) is a min
\((\pm 1,0,2)\) are local minima and \((0,\pm 1, -1)\) are local maxima
all points to consider should be: \((2,-1/3)\text{,}\) \((0,0\)), \((3,0)\text{,}\) \((3,-3)\text{,}\) \((0,-3)\text{,}\) \((2,0)\text{,}\) \((0,-1/3)\text{,}\) \((3,-1/3)\text{,}\) and \((2,-3)\text{;}\) \((2,-1/3,-22/3)\) is a min; \((0,-3,18)\) is a max
\((-8/3, 5/2)\) and \(\sqrt{481}/6\)
-
\((3,-320)\)
\((3,\pm6,-54)\) are saddles and \((0,0,0)\) are all maxima
\((0,1,9/2)\) (D is long — use software!)
icky algebra — use software!
Optimization and Lagrange Multipliers
\((1/2,1/2,1/2)\) is the max, each of \((1,0,0)\) and \((0,1,0)\) is a min
\((0,0,1)\) is the max, each of \((1,0,0)\) and \((0,1,0)\) is a min
there is one saddle on the interior, but no extrema on the interior; the extrema occur on the boundaries at \((0,0),\) \((\pi/2,5),\) \((2,0),\) and \((\pi/2,0)\)
\((12,12,288)\)
\((0, \pm 2)\) and \(\dsp (\pm\frac{\sqrt{15}}{2},1/2)\)
\(x=41, y = 41, z= 41\)